(1)由图可知:∠ABC=45°+90°=135°,
根据勾股定理:BC=
2 2 + 2 2 =2
2 ,
故答案为:135°,2
2 .
(2)△ABC ∽ △DEF,
理由是:AB=2,BC=2
2 ,∠ABC=135°,
EF=2,
DE=
1 2 + 1 2 =
2 ,
∠DEF=90°+45°=135°=∠ABC,
∴
DE
AB =
2
2 ,
EF
BC =
2
2
2 =
2
2 ,
∴
DE
AB =
EF
BC ,
∴△ABC ∽ △DEF.
(1)由图可知:∠ABC=45°+90°=135°,
根据勾股定理:BC=
2 2 + 2 2 =2
2 ,
故答案为:135°,2
2 .
(2)△ABC ∽ △DEF,
理由是:AB=2,BC=2
2 ,∠ABC=135°,
EF=2,
DE=
1 2 + 1 2 =
2 ,
∠DEF=90°+45°=135°=∠ABC,
∴
DE
AB =
2
2 ,
EF
BC =
2
2
2 =
2
2 ,
∴
DE
AB =
EF
BC ,
∴△ABC ∽ △DEF.