f(x)=a.b
∵ sin(π-πx)=sinπx.sin(3π/2-πx)=-cosπx.
∴a=(sinπx,-cosπx).
a.b=√3sinπx+cosπx
=2[(√3/2)sinx+(1/2)cosπx].
=2sin(πx+π/6).
∴f(x)=2sin(πx+π/6).
(1) ∵x∈(0.1/2),f(x)∈(2sinπ/6,2sin2π/3)
∴f(x)∈(1,√3).
∵f(x)=3m+2 有实数解.
∴ 1
已知向量a=[sin(π-πx),sin(3π/2-πx)],b=(√3-1),设f(X)=ab
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