3x^2-9x-33=0,
x^2-3x-11=0
x^2-3x=11
（x+1)(x-1)(x-2)(x-4)
={（x+1）（x-4）}{(x-1)(x-2)}
=(x^2-3x-4)(x^2-3x+2)
=(11-4)(11+2)
=7*13
=91
诺3x^2-9x-33=0,求（x+1)(x-1)(x-2)(x-4)=?
1个回答
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