为区别下标,我用An代替你的an由题意,有 3An ＝A(n-1) ＋2A(n-2)两边同时减去3A(n-1) ,得3An－3A(n-1)＝－2A(n-1) ＋2A(n-2)整理,变形,得,An－A(n-1)＝－2/3*[A(n-1) －A(n-2)]∴ { An－A(n-1)} 是一个新的等比数列 ...
设数列满足an=1,a2=2,an=1/3(an-1+2an-2)(n∈N*且n≥3）,1.求证数列an+1-an是等比
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