3a³b²÷a²+b(a²b-3ab-5a²b)
=3ab²+a²b²-3ab²-5a²b²
=-4a²b²
(-2)³+√(-4)²+³√(-4)³×(﹣1/2)²-³√27
=-8+4+(-4)×1/4-3
=-8+4-1-3
=-8
(3x+1)(2x-3)-(6x-5)(x-4)
=6x²-7x-3-6x²+29x-20
=22x-23
﹙﹣5/2 a n+1的次方b²﹚÷﹙﹣1/4a n的次方b²﹚² · ﹙﹣2/5 a n的次方b n的次方﹚²
=(-5/2a的n+1次方b²)×(2/5a n的次方b n的次方÷1/4a n的次方b²)²
=(-5/2a的n+1次方b²)×(8/5b n-2的次方)²
=-32/5a的n+1次方b的2n-2次方