Question

已知x-1/x=-2,求x^4+x^2+1分之x^2的值

Answer 1

1.因为(x^4+x^2+1)/x^2=x^2 +1/x^2 +1 =(x-1/x)^2 +2+1=(-2)^2 +2+1=7

所以x^2/(x^4+x^2+!)=1/7

2.(x-y分之1+x+y分之1)除x^2-y^2分之xy

=[(x+y)+(x-y)]/(x^2-y^2) ÷[xy/(x^2-y^2)]

=2x/(x^2-y^2)÷[xy/(x^2-y^2)]

=2/y

=2/根号2=根号2