ZnCO3+2Cu2O+C=4Cu*Zn+2CO2
设可日产含铁98%的生铁的质量为x
Fe2O3+3CO==2Fe+3CO2
16 112
5000t×70% x×98%
160/112=5000t×70%/x×98%
x=2500t
Fe3O4--3Fe
232 168
x*90% 2000t*(1-3%)
得x=2976.7t
ZnCO3+2Cu2O+C=4Cu*Zn+2CO2
设可日产含铁98%的生铁的质量为x
Fe2O3+3CO==2Fe+3CO2
16 112
5000t×70% x×98%
160/112=5000t×70%/x×98%
x=2500t
Fe3O4--3Fe
232 168
x*90% 2000t*(1-3%)
得x=2976.7t