A 串(B并C)
损坏率=P(A坏 或 (BC都坏))
=P(A坏)+P(BC都坏)-P(ABC都坏)
=0.3+(0.2*0.2)-(0.3*0.2*0.2)
=0.3+0.04-0.012
=0.34-0.012
=0.328
或由电路好的概率下手
A好且(B或C好)
=A好*(1-BC都坏)
=0.7*(1-0.04)
=0.672
电路坏的概率
1-0.672
=0.328
A 串(B并C)
损坏率=P(A坏 或 (BC都坏))
=P(A坏)+P(BC都坏)-P(ABC都坏)
=0.3+(0.2*0.2)-(0.3*0.2*0.2)
=0.3+0.04-0.012
=0.34-0.012
=0.328
或由电路好的概率下手
A好且(B或C好)
=A好*(1-BC都坏)
=0.7*(1-0.04)
=0.672
电路坏的概率
1-0.672
=0.328