(1)
n(HCl)=1.12/22.4=0.05mol
c(HCl)=0.05/0.25=0.2mol/L
(2)
Zn+2HCl==ZnCl2+H2↑
所以生成的n(H2)=0.05/2=0.025mol
V(H2)=22.4*0.025=0.56L
(1)
n(HCl)=1.12/22.4=0.05mol
c(HCl)=0.05/0.25=0.2mol/L
(2)
Zn+2HCl==ZnCl2+H2↑
所以生成的n(H2)=0.05/2=0.025mol
V(H2)=22.4*0.025=0.56L