√3【1-cos(A+B)]=sinC+√3+1
√3(1+cosC)=sinC+√3+1
√3cosC-sinC=1
√3/2cosC-1/2sinC=1/2
sin(60°-C)=1/2
∵0﹤C﹤180°
∴-120°﹤60°-C﹤60°
∴60°-C=30°
∴C=30°
√3【1-cos(A+B)]=sinC+√3+1
√3(1+cosC)=sinC+√3+1
√3cosC-sinC=1
√3/2cosC-1/2sinC=1/2
sin(60°-C)=1/2
∵0﹤C﹤180°
∴-120°﹤60°-C﹤60°
∴60°-C=30°
∴C=30°