√﹙a²-3a+1﹚+b²+2b+1=0
√﹙a²-3a+1﹚+﹙b+1﹚²=0
∴a²-3a+1=0, b+1=0
a-3+1/a=0,b=-1
a+1/a=3
a²+1/a²=﹙a+1/a﹚²-2=9-2=7
a²+﹙1/a²﹚-|b|=7-1=6
√﹙a²-3a+1﹚+b²+2b+1=0
√﹙a²-3a+1﹚+﹙b+1﹚²=0
∴a²-3a+1=0, b+1=0
a-3+1/a=0,b=-1
a+1/a=3
a²+1/a²=﹙a+1/a﹚²-2=9-2=7
a²+﹙1/a²﹚-|b|=7-1=6