甲乙同时从AB相向而行速度比是3:2第一次相遇后甲速提高20%乙速提高30%这样当甲到B时乙离A14千米AB相距几

1个回答

  • 设AB相距X千米,甲速为:Y千米/小时,则:乙速为:2Y/3千米/小时.

    X-(X/(Y+(2Y/3))*(2Y/3))-((X-(X/(Y+(2Y/3))*Y)/(1.2*Y))*1.3*(2Y/3)=14

    X-(X/(1+(2/3))*(2/3))-((X-(X/(1+(2/3)))/(1.2))*1.3*(2/3)=14

    X-(X/(5/3))*(2/3))-((X-(X/(5/3))/(1.2))*1.3*(2/3)=14

    X-(3X/5)*(2/3)-((X-(3X/5))/(1.2))*1.3*(2/3)=14

    X-(2X/5)-(2X/5)/(1.2)*1.3*(2/3)=14

    3X/5-(2X/5)*1.3*(2/3)/(1.2)=14

    3.6X/5-(2X/5)*1.3*(2/3)=14*1.2=16.8

    3.6X-2X*1.3*(2/3)=84

    10.8X-2X*1.3*2=252

    10.8X-5.2X=252

    5.6X=252

    X=252/5.6=45千米

    AB相距45千米.