已知拱高弦长求弧长我有4个尺寸帮我求弧长,在知道里面看到公式由于文化底看不懂,请帮我直接算结果.弦长2404拱高664弦

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  • 已知拱高H=664弦长L=2404求弧长C?

    弧半径为R,弧所对的圆心角为A.

    R^2=(R-H)^2+(L/2)^2

    R^2=R^2-2*R*H+H^2+L^2/4

    2*R*H=H^2+L^2/4

    R=H/2+L^2/(8*H)

    =664/2+2404^2/(8*664)

    =1419.95

    A=2*ARC SIN((L/2)/R)

    =2*ARC SIN((2404/2)/1419.95)

    =115.667度

    C=PI*R*A/180=PI*1419.95*115.667/180=2866.57

    已知拱高H=669弦长L=1340求弧长C?

    弧半径为R,弧所对的圆心角为A.

    R^2=(R-H)^2+(L/2)^2

    R^2=R^2-2*R*H+H^2+L^2/4

    2*R*H=H^2+L^2/4

    R=H/2+L^2/(8*H)

    =669/2+1340^2/(8*669)

    =670

    A=2*ARC SIN((L/2)/R)

    =2*ARC SIN((1340/2)/670)

    =179.83度

    C=PI*R*A/180=PI*670*179.83/180=2102.87