Question

若函数f(x)满足f(n2)=f(n)+2,n≥根号2,且f(2)=1 求f(16)及f(根号2)

Answer 1

f(n^2)=f(n)+2

=>

f(16)=f(4)+2=f(2)+2+2=1+2+2=5

f(2)=f(√2)+2

=>f(√2)=f(2)-2=1-2=-1