Question

用秦九韶算法求多项式p(x)=3x^5-2x^3+x+7在x=3处的值

Answer 1

p(x)=3x^5+0x^4-2x^3+0x^2+x+7 =(3x^4+0x^3-2x^2+0x+1)x+7 =((3x^3+0x^2-2x+0)x+1)x+7 =(((3x^2+0x-2)x+0)x+1)x+7 =((((3x+0)x-2)x+0)x+1)x+7 v[1]=3x+0=9 v[2]=v[1]x-2=25 v[3]=v[2]x+0=75 v[4]=v[3]x+1=226 v[5]=v[4]x+7=685