Question

若x^2+4x+4+y^2-8y+16=0 求y/x的值 快啊,十万火急!

Answer 1

x^2+4x+4+y^2-8y+16=0

(x+2)^2+(y-4)^2=0

因为(x+2)^2>=0,(y-4)^2>=0

所以x+2=0,y-4=0 -> x=-2,y=4

则y/x=4/-2=-2