∵1/x+x=3
∴x^2=3x-1
∴x^4+3x^3-16^2+3x-15
=(3x-1)x^2+3x^3-16^2+3x-15
=6x^3-17x^2+3x-15
=6x(3x-1)-17x^2+3x-15
=x^2-3x-15
=-1-15
=-16
∵1/x+x=3
∴x^2=3x-1
∴x^4+3x^3-16^2+3x-15
=(3x-1)x^2+3x^3-16^2+3x-15
=6x^3-17x^2+3x-15
=6x(3x-1)-17x^2+3x-15
=x^2-3x-15
=-1-15
=-16