Question

已知等差数列｛an｝满足a3+a6=-1/3,a1*a8=-4/3且a1＞a8求数列｛an}通项公式谢谢了,

Answer 1

因为a3+a6=a1+a8=-1/3,a1*a8=-4/3,又因为a1>a8,所以a1=1,a8=-4/3,因为a8=a1+7d=1+7d=-4/3,所以d=-1/3,所以an=-n/3