解方程1/(xx+x)+1/(xx+3x+2)+1/(xx+5x+6)+1/(xx+7x+12)+1/(xx+9x+20

1个回答

  • 方程左边1/(xx+x)+1/(xx+3x+2)+1/(xx+5x+6)+1/(xx+7x+12)+1/(xx+9x+20)对分母因式分解得

    1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)

    =1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)+1/(x+4)-1/(x+5)

    =1/x-1/(x+5)

    =5/x(x+5)

    所以原方程可化简得

    5/x(x+5)=5/(xx+11x-708)

    方程两边同乘以最简公分母得xx+11x-708=x(x+5)

    解得x=118

    经检验得:x=118是原方程的解