∫sinπx/3dx
=(3/π)∫sinπx/3d(πx/3)
=-(3/π)cos(πx/3)+C
sinπx/3的原函数
1个回答
相关问题
-
已知函数f(x)= [sin(2π-x)sin(π+x)cos(-x-π)] ／[2cos(π-x)sin(3π-x)]
-
设函数f(x)=sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)
-
求函数y=sin(x+π/3)+2sin(x-π/3)的单调增区间
-
已知函数f(x)=sin(π/2-x)-√3sin(π-x)求解
-
求出函数f(x)=sin(x+π/3)+√3sin(x-π/6)的单调增区间.
-
（2010•河东区一模）已知函数f（x）=[sin（[π/4]+x）sin（[π/4]-x）]•sin（[π/3]+x）
-
设函数f（x）=√3 sin（π/4×x-π/3）
-
设函数f(x)sin(x+π/3)+2sin(x+π/3)-根号3cos(2π/3-x) （1）求f(π/6),f(π/
-
已知函数f(x)=cos(2x-π/3）+2sin(x-π/4）sin(x+π/4),求函数f(x)的零点.
-
f(x)=cos(x+π/6）cos(x-2π/3)+sin(x+π/6)sin(x+π/3) 求函数F（X）的单调递减