Question

已知2k的2次方+11k+18=a(k+2)的2次方+b(k+2)+c

Answer 1

a(k+2)的2次方+b(k+2)+c=ak^2+(4a+b)k+4a+2b+c.a=2,4a+b=11,4a+2b+c=18.b=3.c=4