(1)S1=a1;S2=a1(1+q);S3=a1(1-q^3)/(1-q)=a1(1+q+q^2) (分母不为0,得q≠1)
又2S2=S1+S3 化简后得q=0
(2)a1-a3=a1(1-q^2)=3 得a1=3 则Sn=3(1-q^n)/(1-q)=3
可判断{an}是首项为3,其余各项为0的等比数列
(1)S1=a1;S2=a1(1+q);S3=a1(1-q^3)/(1-q)=a1(1+q+q^2) (分母不为0,得q≠1)
又2S2=S1+S3 化简后得q=0
(2)a1-a3=a1(1-q^2)=3 得a1=3 则Sn=3(1-q^n)/(1-q)=3
可判断{an}是首项为3,其余各项为0的等比数列