Question

用三角函数的万能公式求一个被积函数是1/(1+x^4)的不定积分，跪求答案

Answer 1

1+x^4 = (1+x²)² - 2x² = (1+x²+√2x)(1+x²-√2x)1/(1+x^4) = [1/(1+x²-√2x) - 1/(1+x²+√2x)]/2√2x = 1/2√2 *[1/x + (√2-x)/(1+x²-√2x) - 1/x + (√2+x)/(1+x²+√2x)] = 1...