Question

集合A=｛x|x²+4x=0｝集合B=｛x|x²+2（a+1）x+a²-1=0｝

Answer 1

(1).A={0,-4}∵A∩B=B,∴B⊂A①当B=Φ时,判别式△=4(a+1)²-4a²+4=8(a+1)＜0,即a＜-1②当B={0}或者B={-4}时,判别式△=8(a+1)=0,即a=-1,∴B={0}③当B={0,-4}时,判别式△=8(a+1)＞0,即a＞-1且满足0+0+a&...