∫dx/(1-x-a)= -∫d(1-x-a)/(1-x-a)=-ln|1-x-a|+C
∫10^(-y)dy
=∫(1/10)^ydy
=[1/ ln(1/10)] * (1/10)^y +C
∫dx/sinx=∫sinxdx/(1-cosx^2)=-∫dcosx/[(1-cosx)(1+cosx)]=-(1/2)ln|(1+cosx)/(1-cosx)|+C
=-ln|(1+cosx)/sinx|+C
=-ln|cscx+cotx|+C
∫(-10^(-y)/ln10 dy
=(-1/ln10)∫(1/10)^ydy
=(-1/ln10)*(1/ln(1/10))*(1/10)^y +C
=1/(ln10)^2 *(1/10)^y +C