角x的终边经过点p(1,√3)
可知
x是第一象限角,且tanx = √3
所以x = π/3 + 2kπ
sin(π - x) - sin(π/2 + x)
=sin (2/3 * π) - sin(2/3 * π)
= 0
x的集合S为{x|x = π/3 + 2kπ, k∈Z}
亦即x ∈{x|x = π/3 + 2kπ, k∈Z}
角x的终边经过点p(1,√3)
可知
x是第一象限角,且tanx = √3
所以x = π/3 + 2kπ
sin(π - x) - sin(π/2 + x)
=sin (2/3 * π) - sin(2/3 * π)
= 0
x的集合S为{x|x = π/3 + 2kπ, k∈Z}
亦即x ∈{x|x = π/3 + 2kπ, k∈Z}