Question

已知；a.b互为相反数,c,d互为倒数,e的相反数为2,试求e的平方加【a加b加2cd]e加

Answer 1

a.b互为相反数,则a+b=0

c,d互为倒数,则cd=1

e的相反数为2,则e=-2

e^2+(a+b+2cd)e+(a+b)^2002+(-cd)^2003

=(-2)^2+(0+2x1)x(-2)+(0)^2002+(-1)^2003

=4-4+0-1

=-1