7 = log(2)x + 2log(4)x + log(8)x
= log(2)x + 2[log(2)x]/2 + log(2)x/3
= (7/3)log(2)x,
log(2)x = 3
x = 2^3 = 8
对数方程log2x+2log4x+log8x=7求x..(其中log后面的数字是底数...）
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