双曲线y2/4-x2/9=1的渐近线的夹角为?
a=2,b=3,渐近线y=±(3/2)x;K₁=3/2,K₂=-3/2;
设其夹角为α,那么tanα=(k₁-k₂)/(1+k₁k₂)=(3/2+3/2)/(1-9/4)=3/(-5/4)=-12/5
故α=arctan(-12/5)=112.62º;【或α=180º-112.62º=67.38º】
双曲线y2/4-x2/9=1的渐近线的夹角为?
a=2,b=3,渐近线y=±(3/2)x;K₁=3/2,K₂=-3/2;
设其夹角为α,那么tanα=(k₁-k₂)/(1+k₁k₂)=(3/2+3/2)/(1-9/4)=3/(-5/4)=-12/5
故α=arctan(-12/5)=112.62º;【或α=180º-112.62º=67.38º】