Question

已知：|2a-5|+（4a-b-1）²=0 又自然数c满足8ac+16＞3bc 求c的值

Answer 1

由|2a-5|+（4a-b-1）²=0 ,得,

2a-5=0,

4a-b-1=0,

解得a=5/2,

b=9,

代入到8ac+16＞3bc ,得,

20c+16>27c,

所以7c