Question

已知Rt三角形ABC的斜边为AB,点A（-2,0）,B（4,0）,求点C的轨迹方程

Answer 1

设C(x,y)

AC垂直BC

则[(y-0)/(x+2)]*[(y-0)/(x-4)]=-1

y^2=-(x+2)(x-4)

y^2=-x^2+2x+8