等差数列an,bn的前n项和的比为Sn:Sn''=5n+3:2n+7,则a5:b5=?
3个回答
因为等差数列的前9项的均值等于第五项
a5:b5=S9:S9''
n=9带入Sn:Sn''=5n+3:2n+7,
得a5:b5=48:25
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