Question

y=2x/(1-x^2)导数?请写明计算过程

Answer 1

y'=[2x/(1-x^2)]'

=[2x'(1-x^2)-2x*(1-2^x)']/(1-x^2)^2

=[2(1-x^2)+4x^2]/(1-x^2)^2

=2(1+x^2)/(1-x^2)^2