(1)
Sn=48=a1+a2+……+an=48
S2n=a1+a2+……an+a(n+1)+……a(2n)=60
Sn+Sn*q^n=S2n
q^n=1/4
S3n=a1+……a(3n)=S2n+a(2n+1)+……a(3n)=S2n+Sn*q^2n=60+48*(1/4)^2=63
(2)
a(n+1)=2(an)+3
a(n+1)+3=2(an)+6=2(an+3)
a1+3=4
所以{an+3}是以4为首项,2为公比的等比数列
an+3=2^(n+1)
an=2^(n+1)-3
(1)
Sn=48=a1+a2+……+an=48
S2n=a1+a2+……an+a(n+1)+……a(2n)=60
Sn+Sn*q^n=S2n
q^n=1/4
S3n=a1+……a(3n)=S2n+a(2n+1)+……a(3n)=S2n+Sn*q^2n=60+48*(1/4)^2=63
(2)
a(n+1)=2(an)+3
a(n+1)+3=2(an)+6=2(an+3)
a1+3=4
所以{an+3}是以4为首项,2为公比的等比数列
an+3=2^(n+1)
an=2^(n+1)-3