设X轴上的点N(a,0),
MN连线中点必在题给直线上,
且线段MN与题给直线垂直(斜率乘积为-1),
即,2*(a-1)/2 - (0+2)/2 + m = 0
[(0-2)/(a+1)]*2 = -1
解得 m = -1