Question

周期函数求周期疑问,f(x+1)=f(x-1)的周期,这一类周期函数周期求法

Answer 1

设 u = x - 1,则 x = u + 1.因此有：

f(u) = f(x-1) = f(x+1) = f(u+1+1) = f(u+2)

可见,周期是 2.