答案是C(Na+)大于C(CL-)等于C(CH3COOH) .
溶液为中性时,说明盐酸将醋酸钠水解产生的OH-离子正好中和,只限于水电离出H+和OH-
CH3COONa+H2O====CH3COOH+NaOH
----------------------------------1----------1
NaOH+HCl=NaCl+H2O
1---------1-----1
所以C(CL-)等于C(CH3COOH) ,而醋酸钠全部电离,醋酸根只是部分水解,因此C(Na+)大于C(CL-)等于C(CH3COOH) .