Question

己知一元一次方程1/6十2(x十132分之一)=6分之5,求代数式15-30(x+132分之1)

Answer 1

1/6 + 2(x + 1/132) = 5/6

2(x + 1/132) = 5/6 - 1/6

x + 1/132 = 1/3

x = 1/3 - 1/132

x = 43/132

所以 15 - 30( x + 1/132) = 15 - 30× （ 43/132 + 1/132)

= 15 - 30 × 1/3

= 15 - 10

= 5