Question

x/x-3减x+6/x^2-3x加3/x,其中x=3/2

Answer 1

x/x-3减x+6/x^2-3x加3/x

=[x*x-(x+6)+3(x-3)]/x(x-3)

=(x^2-x-6+3x-9)/x(x-3)

=(x^2+2x-15)/x(x-3)

=(x+5)(x-3)/x(x-3)

=(x+5)/x

所以原式

=13/3