由正弦定理:a/sinA=b/sinB=c/sinC=2R可得:
2RsinBcosC=(4RsinA-2RsinC)cosB
sinBcosC+sinCcosB=2sinAcosB
sin(B+C)=2sinAcosB
sin(180-A)=2sinAcosB
sinA=2sinAcosB
cosB=1/2
因为在三角形中,所以B=60或120
由正弦定理:a/sinA=b/sinB=c/sinC=2R可得:
2RsinBcosC=(4RsinA-2RsinC)cosB
sinBcosC+sinCcosB=2sinAcosB
sin(B+C)=2sinAcosB
sin(180-A)=2sinAcosB
sinA=2sinAcosB
cosB=1/2
因为在三角形中,所以B=60或120