√6÷(1/√3-1/√2)
=√6÷(√2/√6-√3/√6)
=√6÷(√2-√3)/√6
=6/(√2-√3)
=6(√2+√3)/[(√2-√3)(√2+√3)]
=6(√2+√3)/(2-3)
=-6(√2+√3)