1.a^2+b^2+2ab-a^2
=b^2+2ab
=b(2a+b)
2.49(a^2-2ab=b^2)-16(a^2+2ab+b^2)
=49a^2-98ab=49b^2-16a^2-32ab-16b^2
=33a^2-130ab+33b^2
3.∵a^2+b^2=(a-b)^2+2ab
∴把已知条件代入得7=25+2ab
∴ab=-9
∵a(a-5)=-9
a^2-5a+9=0
∵△
1.a^2+b^2+2ab-a^2
=b^2+2ab
=b(2a+b)
2.49(a^2-2ab=b^2)-16(a^2+2ab+b^2)
=49a^2-98ab=49b^2-16a^2-32ab-16b^2
=33a^2-130ab+33b^2
3.∵a^2+b^2=(a-b)^2+2ab
∴把已知条件代入得7=25+2ab
∴ab=-9
∵a(a-5)=-9
a^2-5a+9=0
∵△