2sin²2xcos²2x是否等于sin²2x
1个回答
2sin²2xcos²2x
=(4sin²2xcos²2x)/2
=(2sin2xcos2x)²/2
=(sin4x)/2
相关问题
(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x
求证:[1−2sin2xcos2xcos22x−sin22x=1−tan2x/1+tan2x].
化简cos^4x+sin^2xcos^2x+sin^2x
(sin2xcos2x)/2怎么就变成1/2 sin4x,
1、化简函数f(x)=(sin^4 x+cos^4 x+sin^2 xcos^2 x)/(2-sin2x)
求证:tan(x+y)+tan(x-y)=sin2xcos2x−sin2y.
化y=sin^22x+2√3sin2xcos2x+3cos^22x
化简sin^4x+sin^2xcos^2x+cos^2x=?(请写过程)
由sin(-3x-pi/2)是否等于-sin(3x+pi/2)
函数y=sin(2x−5)x的导函数为y=2xcos(2x−5)−sin(2x−5)x2y=2xcos(2x−5)−si