做此题须知:
1/(1+√2)=(√2-1)/[(√2+1)(√2-1)]=√2-1
同理可知
1/(√2+√3)=√3-√2
……
1/(√2007+√2008)=√2008-√2007
所以M=√2008-√2007+√2007-√2006……+√3-√2+√2-1
=√2008-1
所以(M+1)^2=2008
而N=(1-2)+(3-4)……+(2007-2008)
=-1×1004=-1004
所以N/(M+1)^2=-1/2
做此题须知:
1/(1+√2)=(√2-1)/[(√2+1)(√2-1)]=√2-1
同理可知
1/(√2+√3)=√3-√2
……
1/(√2007+√2008)=√2008-√2007
所以M=√2008-√2007+√2007-√2006……+√3-√2+√2-1
=√2008-1
所以(M+1)^2=2008
而N=(1-2)+(3-4)……+(2007-2008)
=-1×1004=-1004
所以N/(M+1)^2=-1/2