化简一个三角函数（2cos^2α-1)/[2tan

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化简(2cos²α-1)/[2tan(π/4-α)sin²(π/4+α)]
化简:(2cos^2α-1)/[2tan(π/4-α)sin^2(π/4+α)]
化简一个三角函数式sin(3π+α）cot(-2π+α）sin(-4π+α）/tan(7π+α）cos(5π+α）能够化
高一三角函数化简.sin²﹙α+π﹚·cos﹙π+α﹚·cot﹙-α－2π﹚/tan﹙π+α﹚·cos²﹙-α－π﹚要
化简（1）sin(α+π)cos(-α)sin(-α-π) （2）sin³（-α）cos（2π+α）tan（-
化简 {sin(π+α)cos(α-2π)tan9π/4}/sin(-α)sin(7π/2+α)
[sin(2π+α）·tan(-α)·cos(-α)]÷[sin(-α)·cos(2π+α）·tan(2π+α）化简
化简cos(α -π )tan(α-2π)tan(2π-α)/sin(π+α)
化简（1）tan(π−α)cos(2π−α)sin(−α+3π2)cos(−α−π)sin(−π−α)．
化简cos(π-α)sin(α+2π)/cos^2(-α-π)tan(2π-α