x+4y+3z=3x-2y-5z=0
则x+4y+3z=0①
3x-2y-5z=0,则6x-4y-10z=0②
①②两式相加,得 7x-7z=0,所以x=z
代入①,得z+4y+3z=0,所以y=-z
所以
x+2y-z/2x-3y+7z=z-2z-z / 2z+3z+7z=-2z /12z=-1/6
已知x+4y+3z=3x-2y-5z=0,求x+2y-z/2x-3y+7z的值
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