三位数XYZ
13(X + Y + Z) = 100X + 10Y + Z
即
87X - 3Y - 12Z = 0
Y + 4Z = 29X
因
0 ≤Y + 4Z ≤ 45,0 ≤ 29X ≤ 45
所以 29X = 29,X = 1
解
Y + 4Z = 29
得
Z = 5 ,Y = 9
Z = 6 ,Y = 5
Z = 7 ,Y = 1
这个三位数可以是:
117、156、195
三位数XYZ
13(X + Y + Z) = 100X + 10Y + Z
即
87X - 3Y - 12Z = 0
Y + 4Z = 29X
因
0 ≤Y + 4Z ≤ 45,0 ≤ 29X ≤ 45
所以 29X = 29,X = 1
解
Y + 4Z = 29
得
Z = 5 ,Y = 9
Z = 6 ,Y = 5
Z = 7 ,Y = 1
这个三位数可以是:
117、156、195