f(x)=sin²x+2sin2x+3cos²x
=1+2sin2x+2cos²x
=1+2sin2x+cos2x+1
=2sin2x+cos2x+2
=√5sin(2x+fai)+2,
其中fai为满足tanfai=1/2和|fai|
设函数F(X)=SIN^2X+2SIN2X+3COS^X(X∈R) 化简为F(X)=ASIN(WX+fai)+K的形式【
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