(1)F=m A
=0.5×
N=0.1 N
由F=m Aω 2L OA=m Bω 2L OB
得m B=m A
=1 kg
(2)x=(v A+v B)t 1=0.6×1.5 m=0.9 m
水平距离为s=
m=1.5 m
(3)t 2=
s=0.5 s
x′=(v A+v B)t 2+a=0.6×0.5 m+2.1 m=2.4 m
距离为s′=
m=
m
(1)F=m A
=0.5×
N=0.1 N
由F=m Aω 2L OA=m Bω 2L OB
得m B=m A
=1 kg
(2)x=(v A+v B)t 1=0.6×1.5 m=0.9 m
水平距离为s=
m=1.5 m
(3)t 2=
s=0.5 s
x′=(v A+v B)t 2+a=0.6×0.5 m+2.1 m=2.4 m
距离为s′=
m=
m