Question

已知函数f(x)=(1/3)x^3_x^2+ax+b的图像在点P(0,f(0))处的切线方程为y=3x_2

Answer 1

f'(x)=x^2-2x+a

f'(0)=a=3

f(0)=b

切线方程为y=3(x-0)+b=3x+b

b=-2